Difference between revisions of "Input.interp"
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| 2.4 (2.0 - 3.2) || # (# - #) ||Lognormal distribution with mean 2.4 and 95 % confidence interval from 2.0 to 3.0. Lognormality is assumed if the difference from mean to upper limit is => 50 % greater than from mean to lower limit.|| | | 2.4 (2.0 - 3.2) || # (# - #) ||Lognormal distribution with mean 2.4 and 95 % confidence interval from 2.0 to 3.0. Lognormality is assumed if the difference from mean to upper limit is => 50 % greater than from mean to lower limit.|| | ||
|---- | |---- | ||
| − | | 24 - 35 (odds 5:1) || # - # (odds #:#) || | + | | 24 - 35 (odds 5:1) || # - # (odds #:#) || Odds is five to one that the truth is between 24 and 35. How to calculate this, I don't know yet, but there must be a prior.|| {{attack|# |I am not sure whether this is actually needed. Who expresses uncertainties in this way?|--[[User:Jouni|Jouni]] 14:00, 28 December 2011 (EET)}} |
|---- | |---- | ||
| + | | 2;4;7 || || Each entry (2, 4, and 7 in this case) are equally likely to occur. Entries can also be text.|| | ||
| + | |---- | ||
| + | | * (in index, or explanatory, columns) || || The result applies to all locations of this index.|| With merge() function, this column is not used as a criterion when these rows are merged. | ||
|} | |} | ||
| + | |||
| + | How to actually make this happen in R? | ||
| + | # Make a temporary result ''temp'' by removing all spaces from Result.Text. Columns: ''Indices,Result.Result.Text,temp'' (Indices contains all explanatory columns.) | ||
| + | # Replace all "," with "." | ||
| + | # Check if there are parentheses "()". If yes, assume that they contain 95 % CI. | ||
| + | # Check if there are ranges "#-#". | ||
| + | # Divide the rows of the data.frame into two new data.frames with the same list of columns (''Indices,Result''). | ||
| + | #* If temp is a syntactically correct distribution, take the row to data.frame A and replace ''Result'' with ''temp''. | ||
| + | #* Otherwise, take the row to data.frame B and replace ''Result'' with ''Result.Text'' if that is not NA. | ||
| + | # Create a new data.frame with index Iter = 1:n. | ||
| + | # Make a random sample from each probability distribution in data.frame A using Iter. | ||
| + | # Merge the data.frame B with Iter. | ||
| + | # Join data.frames A and B with rbind(). Columns: ''Iter,Index,Result''. | ||
Revision as of 12:00, 28 December 2011
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input.interp is an R function that interprets model inputs from a user-friendly format into explicit and exact mathematical format. The purpose is to make it easy for a user to give input without a need to worry about technical modelling details.
Question
What should be a list of important user input formats, and how should they be interpreted?
Answer
The basic feature is that if a text string can be converted to a meaningful numeric object, it will be. This function can be used when data is downloaded from Opasnet Base: if Result.Text contains this kind of numeric information, it is converted to numbers and fused with Result.
n is the number of iterations in the model. # is any numeric character in the text string.
| Example | Regular expression | Interpretation | Output in R |
|---|---|---|---|
| 12 000 | # # | 12000. Text is interpreted as number if space removal makes it a number. | as.numeric(gsub(" ", "", Result.text)) |
| 12,345 | #,# | 12.345. Commas are interpreted as decimal points. | as.numeric(gsub(",", ".", Result.text)) # Note! Do not use comma as a thousand separator! |
| -14,23 | -# | -14.23. Minus in the beginning of entry is interpreted as minus, not a sign for a range. | |
| 50 - 125 | # - # | Uniform distribution between 50 and 125 | data.frame(obs=1:n, result=runif(n,50,125)) |
| -12 345 - -23,56 | Uniform distribution between -12345 and -23.56. | ||
| 1 - 50 | # - # | Loguniform distribution between 1 and 50 (Lognormality is assumed if the ratio of upper to lower is => 30) | |
| 3.1 ± 1.2 or 3.1 +- 1.2 | # ± # or # +- # | Normal distribution with mean 3.1 and SD 1.2 | data.frame(obs=1:n, result=rnorm(n,3.1,1.2)) |
| 2.4 (1.8 - 3.0) | # (# - #) | Normal distribution with mean 2.4 and 95 % confidence interval from 1.8 to 3.0 | data.frame(obs=1:n, result=rnorm(n,2.4,(3.0-1.8)/2/1.96)) |
| 2.4 (2.0 - 3.2) | # (# - #) | Lognormal distribution with mean 2.4 and 95 % confidence interval from 2.0 to 3.0. Lognormality is assumed if the difference from mean to upper limit is => 50 % greater than from mean to lower limit. | |
| 24 - 35 (odds 5:1) | # - # (odds #:#) | Odds is five to one that the truth is between 24 and 35. How to calculate this, I don't know yet, but there must be a prior. | ⇤# : I am not sure whether this is actually needed. Who expresses uncertainties in this way? --Jouni 14:00, 28 December 2011 (EET) |
| 2;4;7 | Each entry (2, 4, and 7 in this case) are equally likely to occur. Entries can also be text. | ||
| * (in index, or explanatory, columns) | The result applies to all locations of this index. | With merge() function, this column is not used as a criterion when these rows are merged. |
How to actually make this happen in R?
- Make a temporary result temp by removing all spaces from Result.Text. Columns: Indices,Result.Result.Text,temp (Indices contains all explanatory columns.)
- Replace all "," with "."
- Check if there are parentheses "()". If yes, assume that they contain 95 % CI.
- Check if there are ranges "#-#".
- Divide the rows of the data.frame into two new data.frames with the same list of columns (Indices,Result).
- If temp is a syntactically correct distribution, take the row to data.frame A and replace Result with temp.
- Otherwise, take the row to data.frame B and replace Result with Result.Text if that is not NA.
- Create a new data.frame with index Iter = 1:n.
- Make a random sample from each probability distribution in data.frame A using Iter.
- Merge the data.frame B with Iter.
- Join data.frames A and B with rbind(). Columns: Iter,Index,Result.
