Difference between revisions of "Metal concentrations in lake sediments"

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(Answer: code improved)
m (Answer)
Line 17: Line 17:
  
 
data <- tidy(op_baseGetData("opasnet_base", "Op_en5462"))
 
data <- tidy(op_baseGetData("opasnet_base", "Op_en5462"))
#print(xtable(data), type = 'html')
 
 
out <- data[data$Observation %in% metalli, ]
 
out <- data[data$Observation %in% metalli, ]
 
colnames(out) <- c("DateTime", "TagName", "Value")
 
colnames(out) <- c("DateTime", "TagName", "Value")
Line 24: Line 23:
 
cat(paste("Metalli: ", metalli, "\n", sep=""))
 
cat(paste("Metalli: ", metalli, "\n", sep=""))
 
plot(out$Value)
 
plot(out$Value)
#multivarplot(out)
 
  
 
</rcode>
 
</rcode>
Line 38: Line 36:
 
library(xtable)
 
library(xtable)
 
library(ggplot2)
 
library(ggplot2)
 +
library(reshape)
  
 
data <- (op_baseGetData("opasnet_base", "Op_en5462"))
 
data <- (op_baseGetData("opasnet_base", "Op_en5462"))
 
data <- tidy(data)
 
data <- tidy(data)
 
#out <- data[data$Observation %in% metalli, ]
 
#colnames(out) <- c("DateTime", "TagName", "Value")
 
#out$Value <- as.numeric(out$Value)
 
#out$DateTime <- as.numeric(out$DateTime)
 
#cat("Metalli: ", metalli, "\n")
 
  
 
data$Result <- as.numeric(data$Result) # This replaces all as.numeric rows below.
 
data$Result <- as.numeric(data$Result) # This replaces all as.numeric rows below.
Line 54: Line 47:
 
data$distance <- sqrt((as.numeric(data$Easting) - easting)^2 + (as.numeric(data$Northing) - northing)^2)
 
data$distance <- sqrt((as.numeric(data$Easting) - easting)^2 + (as.numeric(data$Northing) - northing)^2)
  
#data$Co <- as.numeric(data$Co)
 
#data$Cr <- as.numeric(data$Cr)
 
#data$Cu <- as.numeric(data$Cu)
 
#data$Fe <- as.numeric(data$Fe)
 
#data$Mn <- as.numeric(data$Mn)
 
#data$Ni <- as.numeric(data$Ni)
 
#data$Pb <- as.numeric(data$Pb)
 
#data$S <- as.numeric(data$S)
 
#data$V <- as.numeric(data$V)
 
#data$Zn <- as.numeric(data$Zn)
 
 
#as.data.frame(as.table(tapply(data[, metalli], data[c("distance")], mean)))
 
 
library(reshape)
 
 
data <- melt(data, measure.vars = c("Co", "Cr", "Cu", "Fe", "Mn", "Ni", "Pb", "S", "V", "Zn"))
 
data <- melt(data, measure.vars = c("Co", "Cr", "Cu", "Fe", "Mn", "Ni", "Pb", "S", "V", "Zn"))
#print(xtable(data), type = 'html')
 
  
 
out <- data
 
out <- data

Revision as of 07:48, 6 February 2012



Question

What are metal concentrations in lake sediments? The focus is on Finland.

Answer

Show results


Valitse näytettävä metalli:

+ Show code

Northing:

Easting:

Valitse ympyrän säde(km; järvet ko. alueelta huomioidaan):

Valitse metallit:

+ Show code

Rationale

Based on data from GTK, Finland.

Dependencies

Formula

See also

Keywords

References


Related files

<mfanonymousfilelist></mfanonymousfilelist>

Metal concentrations in lake sediments. Opasnet . [1]. Accessed 02 Jun 2024.